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Q.

A filament bulb 500W, 100V is to be used in a 230Vmain supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500W. The value of  R is

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a

230 Ω

b

46 Ω

c

26 Ω

d

13 Ω

answer is C.

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Detailed Solution

Resistance of bulb, RB=V2P=(100)2500=20ΩPower of the bulb in the circuit, P=VII=PVB=500100=5 AVR=IR⇒(230-100)=5×R∴  R=26Ω
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