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Questions  

A filament bulb 500W100V is to be used in a 230Vmain supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500W. The value of  R is

a
230 Ω
b
46 Ω
c
26 Ω
d
13 Ω

detailed solution

Correct option is C

Resistance of bulb, RB=V2P=(100)2500=20ΩPower of the bulb in the circuit, P=VII=PVB=500100=5 AVR=IR⇒(230-100)=5×R∴  R=26Ω

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