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Q.

A film of liquid is formed between two straight parallel wires each of 10 cm long and at separation 0.5 cm . Calculate the work required to increase the separation between the wires by 1mm. Surface tension of liquid is 72×10−3N/m

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a

144×10−7J

b

124×10−6J

c

82×10−5J

d

94×10−7J

answer is A.

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Detailed Solution

Initial surfacearea=2×10×0.5cm2=10cm2=10×10−4m2Final surface area=2×10×(0.5+0.1)cm2=12cm2=12×10−4m2∴W=T⋅ΔA=72×10−3×2×10−4J=144×10−7J
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