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Q.

A film of liquid is formed between two straight parallel wires each of 10 cm long and at separation 0.5 cm . Calculate the work required to increase the separation between the wires by 1mm. Surface tension of liquid is 72 x 10-3 N/m

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a

144 x 10-7 J

b

124 x 10-6 J

c

82 x 10-5 J

d

94 x 10-7 J

answer is A.

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Detailed Solution

Initial surface area =2 x 10 x 0.5 cm2=10 cm2=10 x 10-4m2Final surface area =2 x 10 x (0.5+0.1) cm2=12 cm2=12 x 10-4m2∴W=T.∆A=72 x 10-3 x 2 x 10-4J=144 x 10-7 J
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