First slide

Simple hormonic motion

Question

Find the average kinetic energy of a simple harmonic oscillator if its total energy is 10 joule and minimum potential energy is 2 joule.

Easy

A

1J
B

4J
C

8J
D

5J

Solution

$TE = {KE}_{\max} + {PE}_{\min}; {KE}_{avg} = \frac{{KE}_{\max}}{2}$

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