Find A+B and A-B in the diagram shown in figure. Given A=4 units and B=3 units.

Addition R=A2+B2+2ABcosθ=16+9+2×4×3cos60°=37 units  tanα=BsinθA+Bcosθ =3sin60°4+3cos60°=0.472 α=tan-1(0.472)=25.3° Thus, resultant of A and B is 37 units at angle 25.3° from A in the direction shown in figure Subtraction S=A2+B2-2ABcosθ=16+9-2×4×3cos60°=13 units  And tanα=BsinθA-Bcosθ=3sin60°4-3cos60°=1.04 α=tan-1(1.04)=46.1°  Thus, A-B is 13 units at 46.1° from A in the direction shown in figure