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Find the Binding energy per neucleon for $_{50}^{120} S n$ . Mass of proton $m_{p} = 1.00783 U$ , mass of neutron $m_{n} = 1.00867 U$ and mass of tin nucleus $m_{S n} = 119.902199 U$ . (take 1U = 931 MeV)

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8.5 MeV

8.0 MeV

7.5 MeV

9.0 MeV

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detailed solution

Correct option is A

BEPN=B.ENo of Nucleons = Zmp+(A-Z)mn-Mnucleus931 MeVA =50×1.00783+70×1.00867−119.902199931120=8.50 MeV

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Find the Binding energy per neucleon for 50120Sn. Mass of proton mp=1.00783 U, mass of neutron mn=1.00867 U and mass of tin nucleus mSn=119.902199 U. (take 1U = 931 MeV)

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Find the Binding energy per neucleon for $_{50}^{120} S n$ . Mass of proton $m_{p} = 1.00783 U$ , mass of neutron $m_{n} = 1.00867 U$ and mass of tin nucleus $m_{S n} = 119.902199 U$ . (take 1U = 931 MeV)