Find the Binding energy per neucleon for 50120Sn. Mass of proton mp=1.00783 U, mass of neutron mn=1.00867 U and mass of tin nucleus mSn=119.902199 U. (take 1U = 931 MeV)
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
8.5 MeV
b
8.0 MeV
c
7.5 MeV
d
9.0 MeV
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
BEPN=B.ENo of Nucleons = Zmp+(A-Z)mn-Mnucleus931 MeVA =50×1.00783+70×1.00867−119.902199931120=8.50 MeV