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Q.

Find the change in internal energy in joule.  When 10g of air is heated from 30°C to 40°C (Cv = 0.172 kcal/kg K, J = 4200 J/kcal)

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a

62.24 J

b

72.24 J

c

52.24 J

d

82.24 J

answer is B.

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Detailed Solution

m = 10 × 10–3kgΔT = T2 – T1 = 40 – 30 = 10oC Cv = 0.172k.cal/kg–k ; here (ΔQ)v = ΔU
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