Find the change in internal energy in joule. When 10g of air is heated from 30°C to 40°C (Cv = 0.172 kcal/kg K, J = 4200 J/kcal)

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62.24 J

72.24 J

52.24 J

82.24 J

answer is B.

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Detailed Solution

m = 10 × 10–3kgΔT = T2 – T1 = 40 – 30 = 10oC Cv = 0.172k.cal/kg–k ; here (ΔQ)v = ΔU

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