Questions
Find the change in internal energy in joule. When 10g of air is heated from 30°C to 40°C (Cv = 0.172 kcal/kg K, J = 4200 J/kcal)
detailed solution
Correct option is B
m = 10 × 10–3kgΔT = T2 – T1 = 40 – 30 = 10oC Cv = 0.172k.cal/kg–k ; here (ΔQ)v = ΔUTalk to our academic expert!
Similar Questions
Two rigid boxes containing different ideal gases are placed on a table. Box A contains one mole of nitrogen at temperature , while Box B contains one mole of helium at temperature (7/3) T0. The boxes are then put into thermal contact with each other and heat flows between them until the gases reach a common final temperature (ignore the heat capacity of boxes). Then, the final temperature of the gases T1 , in terms of T0 is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
