First slide

Dimensions of physical quantities

Question

Find the dimensional formula of Acceleration.

Easy

A

$[{LT}^{- 3}]$
B

$[{LT}^{- 2}]$
C

$[{LT}^{0}]$
D

$[{LT}^{- 1}]$

Solution

$Acceleration, [a] = [\frac{dv}{dt}] [a] = \frac{dv \to kind of velocity}{dt \to kind of time} = \frac{[{LT}^{- 1}]}{[T]} = [{LT}^{- 2}]$

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