First slide

Dimensions of physical quantities

Question

Find the dimensional formula of Universal constant of gravitation, $G$ .

Easy

A

$[M^{- 1} L^{- 3} T^{- 2}]$
B

$[M^{- 1} L^{3} T^{- 2}]$
C

$[M^{1} L^{- 3} T^{- 2}]$
D

$[M^{- 1} L^{- 3} T^{- 3}]$

Solution

$F = \frac{G m_{1} m_{2}}{r^{2}} \Rightarrow G = \frac{F r^{2}}{m_{1} m_{2}} = \frac{[M L T^{- 2}] [L^{2}]}{[M^{2}]} = [M^{- 1} L^{3} T^{- 2}]$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App