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Find $\frac{dy}{dx} for y = \frac{2}{\sqrt{x}} + x \sqrt{x .}$

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-1x32+22x

-1x32+3x2

-2x32+32x

-1x32+32y

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detailed solution

Correct option is B

dydx=ddx2x-12+x32⇒dydx=2-12x-12-1+32x32-1 ⇒dydx=-1x32+3x2

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Find dydx for y=2x+xx.

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Find $\frac{dy}{dx} for y = \frac{2}{\sqrt{x}} + x \sqrt{x .}$