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Q.

Find the electric field at point P (as shown in figure) on the perpendicular bisector of a uniformly charged thin wire of length L carrying a charge Q. The distance of the point P from the centre of the rod is  a=32L.

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a

Q4πε0L2

b

Q23πε0L2

c

3Q4πε0L2

d

Q3πε0L2

answer is B.

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Detailed Solution

Enet=λ4πε0r(sinα+sinβ)hereλ=QL,   r=32L,   sinα=sinβ=12⇒Enet=2Q4πε03L2(12+12)⇒Enet=Q23πε0L2
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