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Q.

Find the frequency of minimum distance between compression & rarefaction of a wire. If the length of the wire is 1m & velocity of sound in air is 360 m/s

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a

90 sec–1

b

180s–1

c

120 sec–1

d

360 sec–1

answer is A.

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Detailed Solution

The minimum  distance between compression and rarefaction of the wire l=λ2  ∴ Wave length  λ=2l Now by v=nλ⇒n=3602×1=180sec−1.
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