Find the magnetic field at the centre of the circular loop as shown in the figure, when a single wire is bent to form a circular loop and also extends to form straight sections.

Question

Infinity Learn · Accepted Answer

Magnetic field due to AB,B→$$1$$  $$=$$  μ$$0I4$$$$π$$R  $$sin$$ π$$2$$−$$sin$$ π$$4$$⊗$$=$$  μ$$0I4$$$$π$$R  $$1$$−$$12$$ ⊗Magnetic field due to circular loop,B→$$2=$$  μ$$0I4R$$ ⊙Magnetic field due to straight wire BC,$$B3=$$  μ$$0I4$$$$π$$R $$sin$$ π$$2+$$$$sin$$ π$$4$$⊙$$=$$  μ$$0I4$$$$π$$$$R1+12$$ ⊙  B→  $$=B$$→$$1$$ $$+$$ B→$$2$$  $$+$$  B→$$3=$$ μ$$0I2R$$ $$+$$ $$2$$μ$$0I4$$$$π$$R − $$12$$ ⊙ $$=$$ μ$$0I2R$$ $$1+12$$ π ⊙

Find the magnetic field at the centre of the circular loop as shown in the figure, when a single wire is bent to form a circular loop and also extends to form straight sections.

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