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Q.

Find the percentage error in specific resistance given by ρ=πr2Rl, where r is the radius having value (0.2±0.02)cm, R is the resistance of (60±2) ohm and l is the length of (150±0.1)cm.

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a

30%

b

27.3%

c

23.4%

d

24.3%

answer is C.

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Detailed Solution

Δρρ×100=2Δrr+ΔRR+ΔIl×100=2×0.020.2+260+0.1150×100=23.4%
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