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Find the percentage error in specific resistance given by ρ=πr2Rl, where r is the radius having value (0.2±0.02)cm, R is the resistance of (60±2) ohm and l is the length of (150±0.1)cm.

a
30%
b
27.3%
c
23.4%
d
24.3%

detailed solution

Correct option is C

Δρρ×100=2Δrr+ΔRR+ΔIl×100=2×0.020.2+260+0.1150×100=23.4%

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