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Questions  

Find the potential V of an electrostatic field E=a(yi^+xj^), where a is a constant.

a
axy+C
b
−axy+C
c
axy
d
−axy

detailed solution

Correct option is B

E→=a(yi^+xj^)V2−V1=−∫(ay dx+ax dy)Take V1=C and V2=V. ThenV=−a∫(ydx+xdy)+C=−a∫d(yx)+C=−axy+C

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