First slide
KVL
Question

Find the reading of the ideal ammeter connected in the given circuit. Assume that the cells have negligible internal resistance.

Moderate
Solution

Inloop  efhge,  4I2+2I1+8=0  In  loopcdfec,  8I3+4I24=0  In  loopabdca,  10I4+8I3+10=0 in loop abjia -10I4-6+8-4+10=0 I4=810=45A, I3=-14A, I2=12A, I1=-3A

Current through ammeter =I1+I2+I3+I4

=60+105+1620  =3920A=1.95  A

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