Find the reading of the ideal ammeter connected in the given circuit. Assume that the cells have negligible internal resistance.
0.8 A
0.25 A
1.95 A
0.05 A
In loop efhge, −4I2 +2I1+8 =0 ⇒In loop cdfec, −8I3 +4I2−4 =0 ⇒ In loop abdca, −10I4 +8I3+10 =0 in loop abjia -10I4-6+8-4+10=0 I4=810=45A, I3=-14A, I2=12A, I1=-3A
Current through ammeter =I1+I2+I3+I4
=−60+10−5+1620 =3920 A=1.95 A