Find the resulting temperature when a motor-car tyre has a pressure of 2 atmosphere at 27oC and it suddenly bursts. If (CP/CV )=1.4 for air.

TγP1−γ=constantor TP(1−γ)/γ=constant     orT1P1(1−γ)/γ=T2P2(1−γ)/γor T2=T1p1P2(1−γ)/γor T2=T1P2P1(γ−1)/γ=300×120.4/1.4=300(2)2/7or T2=246K=−27∘C