Find the value of R for which no current will flow through 5 V battery.
4 Ω
3.5 Ω
3 Ω
5 Ω
If no current flows through 5V battery then potential difference across/and e is 5 V. So potential difference across d and c is also 5 V.
i=10R+1iR=5 ⇒ 10R+1 R=5 ⇒ R=1 Ω