Find the value of 2sin45°cos15°
3+22
0
3+12
2+12
sinC+sinD=2sinC+D2cosC-D2
∴ C+D2=45°
or
C+D=90°
C-D2=15°
C-D=30°
Solving these two equations, we get;
C=60°,D=30°
∴2sin45°cos15°=sin60°+sin30°
=3+12