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Questions  

Find the value of 2sin45°cos15°

a
3+22
b
0
c
3+12
d
2+12

detailed solution

Correct option is C

sinC+sinD=2sinC+D2cosC-D2∴  C+D2=45°or C+D=90°C-D2=15°orC-D=30°Solving these two equations, we get;C=60°,D=30°∴2sin45°cos15°=sin60°+sin30°=3+12

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