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Find the value of 2sin45°cos15°

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a

3+22

b

0

c

3+12

d

2+12

answer is C.

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Detailed Solution

sinC+sinD=2sinC+D2cosC-D2∴ C+D2=45°or C+D=90°C-D2=15°orC-D=30°Solving these two equations, we get;C=60°,D=30°∴2sin45°cos15°=sin60°+sin30°=3+12

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