Q.

Find work done by the gas in the process shown in figure:

Moderate

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52πatmL

52atmL

−32πatmL

−54πatmL

answer is 4.

(Detailed Solution Below)

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Detailed Solution

Area of cycle =|W|=π(4−3)(4−2)2+π(2−1)(3−2.5)2=2.5π2=5π4atmLW=−5π4 atm L work done by the gas.

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