First slide

Heat ;work and internal energy

Question

Find work done by the gas in the process shown in figure:

Moderate

A

$\frac{5}{2} πatmL$
B

$\frac{5}{2} atmL$
C

$- \frac{3}{2} πatmL$
D

$- \frac{5}{4} πatmL$

Solution

Area of cycle $= | W |$
$= \frac{π (4 - 3) (4 - 2)}{2} + \frac{π (2 - 1) (3 - 2 .5)}{2}$
$= \frac{2 .5 π}{2} = \frac{5 π}{4} atmL$
$W = - (\frac{5 π}{4}) atm L$ work done by the gas.

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