Find the work done by an ideal gas during a closed cycle 1 – 4 – 3 – 2 – 1 as shown if P1 = 105 Pa, P0 = 3 ×105 Pa, P2 = 4 ×105 Pa, V2 – V1 = 100 litre and segments 4 – 3 and 2 – 1 of the cycle are parallel to the V – axis.

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7500 J

8000 J

6000 J

None of these

answer is A.

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Detailed Solution

Work done = Area 021 – Area 043=12V2−V1P0−P0−12V4−V3P2−P0=12100×10−32×105−12P2−P0P0−P1V2−V1P2−P0=104−121052×105×100×10−3105J=104−2500=7500J

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