Q.
Find the work done at the end of displacement 60cm in the graph shown.
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a
-1.5J
b
1.5J
c
15J
d
-1J
answer is B.
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Detailed Solution
Work done =Area of Force-displacement graph W=Area of triangleΔOAE+Area of rectangle▭ ABFE+Area of triangle Δ BCF-Area of triangle Δ CGH W=12×20×5+20×5+12×10×5−12×10×51100 here displacement is in cm ,hence conversion factor is taken 1cm=1100meter W=(50+100)1100 W=150100 Work done=1.5J
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