Q.

Find the work done at the end of displacement 60cm in the graph shown.

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a

-1.5J

b

1.5J

c

15J

d

-1J

answer is B.

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Detailed Solution

Work done =Area of Force-displacement graph W=Area of triangleΔOAE+Area  of rectangle▭ ABFE+Area of triangle Δ  BCF-Area ​​  of triangle Δ CGH W=12×20×5+20×5+12×10×5−12×10×51100         here displacement is in cm ,hence conversion factor is taken 1cm=1100meter W=(50+100)1100 W=150100 Work done=1.5J
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