In finding the electric field using Gauss law the formula E→$$=qenc$$∈$$0A$$→ is applicable. In the formula ∈$$0$$ is permittivity of free space, A is the area of Gaussian surface and qenc is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?

Question

In finding the electric field using Gauss law the formula E→$$=qenc$$∈$$0A$$→  is applicable. In the formula ∈$$0$$  is permittivity of free space, A is the area of Gaussian surface and qenc  is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?

Infinity Learn · Accepted Answer

Gauss Law, ∮E→.dA→$$=qenc$$∈$$0$$​⇒∮E→ dA→ $$cos$$θ $$=$$ qenc∈$$0If$$ E→ is perpendicular to surface at all points , then angle between​electric field and area vector is $$0o$$.  It means surface is equipotential⇒∮E→ dA→ $$=$$ qenc∈$$0$$​If E→ is constant, it can be taken out of integration sign, ⇒E→ ∮dA→ $$=$$ qenc∈$$0$$​⇒E→ A→ $$=$$ qenc∈$$0$$⇒E→ $$=qenc$$∈$$0A$$→

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In finding the electric field using Gauss law the formula E→=qenc∈0A→ is applicable. In the formula ∈0 is permittivity of free space, A is the area of Gaussian surface and qenc is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?

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