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Q.

A fireman weighing 80 kg slides down a vertical pole. If the resisting force of friction is a constant value of 720 N, his acceleration in m/s2 is (g = 10 m/s2)

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a

0.01

b

1

c

0.1

d

0.03

answer is B.

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Detailed Solution

F=M(g−a)720=80(10−a)⇒a=1 ms−2
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