The first line in the Lyman series has wavelength λ. The wavelength of the first line in Balmer series is
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a
29 λ
b
92 λ
c
527 λ
d
275λ
answer is D.
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Detailed Solution
For first line in Lyman series λL1=43 R-------(i)For first line in Balmer series λB1=365 R------(ii)From equation (i) and (ii) λB1λL1=275⇒λB1=275λL1⇒λB1=275λ