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Questions  

 A fish is vertically below a flying bird moving vertically down toward water surface. The bird will appear to the fish to be

a
moving faster than its  actual speed and also away  from the real distance
b
moving faster than its real speed and nearer than its real distance.
c
moving slower than its real speed and also nearer than its real distance.
d
moving slower than its real speed and away from the real distance.

detailed solution

Correct option is A

μ1−u+μ2v=μ2−μ1R For a plane surface, R=∞∴ μ1−u+μ2v=0or μ2v=μ1u or μv=1uor v=μ2uClearly, to the fish, the bird appears farther than its actual distance. Again, dvdt=μdudtor Apparent speed of bird = Refractive index x Actual speed of bird.

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