First slide

Ray optics

Question

A fish is vertically below a flying bird moving vertically down toward water surface. The bird will appear to the fish to be

Easy

A

moving faster than its speed and also away from the real distance
B

moving faster than its real speed and nearer than its real distance
C

moving slower than its real speed and also nearer than its real distance
D

moving slower than its real speed and away from the real distance

Solution

$\frac{1}{μ_{w a t e r}} = \frac{d_{r e a l}}{d_{a p p a r e n t}} = \frac{v_{r e a l}}{v_{a p p a r e n t}}$
So, speed and distance both increases. Therefore , bird will appear to be moving fast also its distance will be more than the real distance.

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