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Q.

In a fission reaction U 92236→X 117+Y 117+n+n, the binding energy per nucleon of X and Y is 8.5 MeV where as of U 236 is 7.6 MeV. The total energy liberated will be about

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a

200 KeV

b

2 MKeV

c

200 MeV

d

2000 MeV

answer is C.

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Detailed Solution

∆E=8.5 x 234 - 7.6 x 236=195.4 MeV =200 MeV

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