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In a fission reaction ${}_{92}^{236}U \to {}^{117}X + {}^{117}Y + n + n,$ the binding energy per nucleon of X and Y is 8.5 MeV where as of ${}^{236}U$ is 7.6 MeV. The total energy liberated will be about

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detailed solution

Correct option is C

∆E=8.5 x 234 - 7.6 x 236=195.4 MeV =200 MeV

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In a fission reaction U 92236→X 117+Y 117+n+n, the binding energy per nucleon of X and Y is 8.5 MeV where as of U 236 is 7.6 MeV. The total energy liberated will be about

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In a fission reaction ${}_{92}^{236}U \to {}^{117}X + {}^{117}Y + n + n,$ the binding energy per nucleon of X and Y is 8.5 MeV where as of ${}^{236}U$ is 7.6 MeV. The total energy liberated will be about