Question

Five balls A,B,C,D and E are projected with the same speed making angles of 10^o, 30^o, 45^o, 60^o and 80^o respectively with the horizontal. Which ball will strike the ground at the farthest point?

Easy

Solution

The horizontal range of a projectile is given by
$R = \frac{u^{2} \sin 2 θ}{g}$
The range R is maximum when $\sin 2 θ$ is maximum. Thus
$\sin 2 θ = 1 or 2 θ = π / 2$
or $θ = π / 4$
$∴$ $θ = 45^{\circ}$
So, the body C will have the maximum range.

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