Five capacitors 10 μF capacity each are connected to a D.C. potential of 100 volts as shown in fig. The equivalent capacitance between the points A and B will be equal to

The given circuit is equivalent to Wheat stone's bridge. when the bridge is balanced, the upper two condensers between A and B will be in series. Their resultant capacitance would be1C′=110+110=210=15or     C′=5μFSimilarly, the lower two condensers between A and B are also in series. Their resultant capacitance would be 1C′′=110+110=210=15or    C′′=5μFThe capacitor C' and C'' will then be in parallel. Hence the effective capacitance between A and B will be C=C′+C′′=5+5=10μF