In five complete rotations, the distance moved by screw on a linear scale is 0.5 cm. There are 100 divisions on circular scale. While measuring the thickness of a metal plate by the screw gauge, there are five divisions on the main scale and 35 divisions coincide with the reference line. Calculate the thickness of metal plate,

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5.35 cm

0.535 cm

0.6 cm

0.7 cm

answer is B.

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Detailed Solution

Least count = Pitch Number of divisions on circular scale =0.55100=0.1100 cm=0.001 cmThickness = 5×0.1+35×0.001=0.535 cm

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