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Q.

A flake of glass (refractive index 1.5) is placed over one of the openings of a double slit apparatus. The interference pattern displaces itself through seven successive maxima towards the side where the flake is placed. if wavelength of the diffracted light is λ=600 nm, then the thickness of the flake is

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a

2100 nm

b

4200 nm

c

8400 nm

d

None of these

answer is C.

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Detailed Solution

Shift =βλ(μ−1)t ⇒7β=βλ(μ−1)t⇒t=7λ(μ−1)=7×600(1.5−1)=8400 nm
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A flake of glass (refractive index 1.5) is placed over one of the openings of a double slit apparatus. The interference pattern displaces itself through seven successive maxima towards the side where the flake is placed. if wavelength of the diffracted light is λ=600 nm, then the thickness of the flake is