A flood light will be covered with filter that transmits red light. The electric field of the emerging beam is represented by a sinusoidal plane wave
$E_{X} = 38.8 \sin (1.2 \times 10^{7} z - 3.6 \times 10^{15} t) \frac{v}{m}$
The average intensity of beam in $\frac{w a t t}{m^{2}}$ will be

Question

Infinity Learn · Accepted Answer

Average intension  $$Iave=12$$∈o $$Eo2CThe$$ given equation is $$EX=38.8sin1.2$$×$$107z$$−$$3.6$$×$$1015tvm$$ Is compared with general $$equationEx=Eosinkz$$−wt $$thenEo=38.8$$ $$V/m$$ Hence, $$Iave=12$$×$$8.85$$×$$10$$−$$12$$×$$38.82$$×$$3$$×$$108Iave=2$$ $$W/m2$$

Electromagnetic waves and its nature

Remember concepts with our Masterclasses.

A flood light will be covered with filter that transmits red light. The electric field of the emerging beam is represented by a sinusoidal plane wave
$E_{X} = 38.8 \sin (1.2 \times 10^{7} z - 3.6 \times 10^{15} t) \frac{v}{m}$
The average intensity of beam in $\frac{w a t t}{m^{2}}$ will be

Ready to Test Your Skills?

free study material

Electromagnetic waves and its nature

Remember concepts with our Masterclasses.

A flood light will be covered with filter that transmits red light. The electric field of the emerging beam is represented by a sinusoidal plane waveEX=38.8sin1.2×107z−3.6×1015tvm The average intensity of beam in wattm2 will be

Average intension Iave=12∈o Eo2CThe given equation is EX=38.8sin1.2×107z−3.6×1015tvm Is compared with general equationEx=Eosinkz−wt thenEo=38.8 V/m Hence, Iave=12×8.85×10−12×38.82×3×108Iave=2 W/m2

Ready to Test Your Skills?

free study material

A flood light will be covered with filter that transmits red light. The electric field of the emerging beam is represented by a sinusoidal plane wave
$E_{X} = 38.8 \sin (1.2 \times 10^{7} z - 3.6 \times 10^{15} t) \frac{v}{m}$
The average intensity of beam in $\frac{w a t t}{m^{2}}$ will be