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Q.

The flux linked with a coil at any instant t is given by ϕ=10t2−50t+250. The induced e.m.f. at t = 3 sec is :

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a

190 volt

b

−190 volt

c

−10 volt

d

10 volt

answer is C.

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Detailed Solution

ϕ=10t2−50t+250 Induced em,mf=−dϕdt=−ddt10t2−50t+250=−(20t−50)The induced e.m.f. at t = 3 sece=−(20×3−50)=−(60−50)=−10V
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