Flux passing through the shaded surface of a sphere when a point charge q is placed at the center is (radius of the sphere is R)

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q/ε0

q/2ε0

q/4ε0

zero

answer is C.

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Detailed Solution

α=600. Solid angle subtended by BCD isω=2π(1−cosα)=πSolid angle subtended by ABDE isω(ABCDE)−ω(BCD)=2π−π=πHence, flux through ABDE isϕ=qε0π4π=q4ε0

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