First slide

Gauss's law and its applications

Question

The flux (in Vm) of electric field $\vec{E} = 200 \hat{i}$ N/C through a cube of side 10cm, oriented so that its faces are parallel to the coordinate axes is

Easy

Solution

The flux through surfaces ABCD and EFGH is zero $(ϕ = E d s \cos 90 ° = 0)$ .
Flux through face BFGC $(ϕ_{1} = E d s \cos 0 ° = E d s)$
Flux through face AEHD $(ϕ_{2} = E d s \cos 180 ° = - E d s)$
Total flux= $ϕ_{1} + ϕ_{2} = E d s - E d s = 0$

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