A flywheel, in the form of a solid disc, of mass $$25$$ kg has a radius of $$0.2$$ m. It is making $$240$$ rpm. If the torque is due to a force applied tangentially on the rpm of the fly wheel, what is the magnitude of the force to bring it to rest in $$20$$ $$sec$$ ?

Question

Infinity Learn · Accepted Answer

$$I=12$$ ×  $$25$$  ×$$0.22$$  kg−$$m2=0.5$$  kg−$$m2$$α  $$=$$  ω$$0t$$ $$=$$  π×$$24030$$ ×$$20$$  $$rad/s2=1.256$$  $$rad/sec2$$∴   τ$$=F$$     $$R=I$$ α⇒  $$F=0.5$$  ×  $$1.2560.2$$   $$N=3.14N$$

A flywheel, in the form of a solid disc, of mass 25 kg has a radius of 0.2 m. It is making 240 rpm. If the torque is due to a force applied tangentially on the rpm of the fly wheel, what is the magnitude of the force to bring it to rest in 20 sec ?

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