First slide

The lens

Question

Focal length of a converging lens in air is R. If it is dipped in water of refractive index 1.33, then its focal length will be around (Refractive index of lens material is 1.5)

Moderate

A

R
B

2R
C

4R
D

$\frac{R}{2}$

Solution

$\frac{f_{l}}{f_{a}} = \frac{a^{μ_{g}} - 1}{_{l} μ_{g} - 1} \Rightarrow f_{l} = 4 R$

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