First slide

The lens

Question

The focal length of a convex lens is 10 cm and its refractive index is 1.5. If the radius of curvature of one surface is 7.5 cm, the radius of curvature of the second surface will be

Moderate

A

7.5 cm
B

15.0 cm
C

75 cm
D

5.0 cm

Solution

$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}) \Rightarrow \frac{1}{+ 10} = (1 .5 - 1) (\frac{1}{+ 7 .5} - \frac{1}{R_{2}}) \Rightarrow R_{2} = - 15 cm$

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