Q.

Focal length of convex lens is 'f'. Find the position of real object for which virtual image is 4 times the size of object.

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a

−f

b

−0.25f

c

-0.50 f

d

−0.75f

answer is D.

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Detailed Solution

n=vu⇒1nu−1u=1f⇒1u1−nn=1f⇒u=f(1−n)n=f(1−4)4=−3f4=−0.75
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