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Q.

The focal lengths of a lens are in the ratio 6:2  when it is immersed in two different liquids of refractive indices 1.5 and 1.3 respectively. The refractive index of the material of the lens is

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a

1. 6

b

1. 5

c

1.4

d

1.2

answer is A.

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Detailed Solution

f1f2=(μ−μ2μ−μ1)μ1μ2 632=(μ−1.3μ−1.5)1.50.51.3⇒1.3μ−1.95=0.5μ−0.65 0.8μ=1.3 μ=138=1.6
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