First slide

CIrcuit questions

Question

In the following circuit $E_{1} = 12 volt$ and zero internal resistance while the battery $E_{2} = 2 volt$ and also has zero internal resistance. If the reading of galvanometer is zero, the value of resistance ‘X’ in ohm is

Moderate

A

10
B

100
C

500
D

200

Solution

$\begin{array}{l} i = \frac{12}{(500 + x)} A . \\ ∴ ix = \frac{12 x}{500 + x} = 2 \Rightarrow x = 100 Ω \end{array}$

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