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An Intiative by Sri Chaitanya
a
is 0
b
is 1
c
fluctuates between 0 and 1
d
is indeterminate as the circuit can't be realised
answer is A.
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Detailed Solution
Lower NOT gate inverts input 1 to zero. NOT gate and NAND gate inverts this output 0 to Upper NAND gate converts this output 1 and input 0 to 1. Thus A = 1 and B = 1 become inputs of NAND gate giving final output as zero. Choice (1) is correct.