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Q.

In the following common emitter circuit, if β=100.VCE=7V,VBE= negligible, RC=2kΩ , then IB= ?

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An Intiative by Sri Chaitanya

a

0.01 mA

b

0.04mA

c

0.02mA

d

0.03mA

answer is B.

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Detailed Solution

V=VCE+ICRC⇒15=7+IC×2×103⇒ic=4mA∵β=iCiB⇒iB=4100=0.04mA

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