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Questions  

In the following common emitter circuit, if β=100, VCE=7V,VBE=negligible, RC=2,then  IB=?

a
0.01 mA
b
0.04 mA
c
0.02 mA
d
0.03 mA

detailed solution

Correct option is B

V=VCE+ICRL⇒15=7+IC×2×103⇒IC=4  mA∵β=ICIB⇒IB=4100=0.04 mA

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In the circuit shown, the base current is 30 µA. The value of R1 is (Neglect VBE)


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