In the following common emitter circuit, if β=100, VCE=7V,VBE=negligible, RC=2kΩ, then IB=?
0.01 mA
0.04 mA
0.02 mA
0.03 mA
V=VCE+ICRL⇒15=7+IC×2×103⇒IC=4 mA∵β=ICIB⇒IB=4100=0.04 mA