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Questions  

In the following common emitter circuit if  β=100, VCE=7 V, VBE is negligible, Rc=2 , then IB = 

 

 

a
0.01 mA
b
0.04 mA
c
0.02 mA
d
0.03 mA

detailed solution

Correct option is B

VCC=VCE+ICRc15=7+Ic×2×103IC=4 mAβ=IcIBIB=Icβ=4100 mA=0.04 mA

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