Questions
In the following common emitter circuit if , then IB =
detailed solution
Correct option is B
VCC=VCE+ICRc15=7+Ic×2×103IC=4 mAβ=IcIBIB=Icβ=4100 mA=0.04 mATalk to our academic expert!
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In a common-base mode of transistor, the collector current is 5 488 mA for an emitter current of 5 .60 mA. The value of the base current amplification factor (p) will be
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