In the following common emitter configuration, an n-p-n transistor with current gain, β=100 is used. The output voltage of the amplifier will be
10 mV
0.1 V
1.0 V
10 V
Given that,
β=100
Ri=1kΩ
RL=10KΩ
Vi=ΔVBE=1mv
voltage gain
AV=ΔVCEΔVBE=β×RLRi
ΔVCE=ΔVBE×β×RLRI
ΔVCE=1×10−3×100×101=1.0V