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In the following common emitter configuration, an n-p-n transistor with current gain, $β = 100$ is used. The output voltage of the amplifier will be

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10 mV

0.1 V

1.0 V

10 V

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detailed solution

Correct option is C

Given that,β=100Ri=1kΩRL=10KΩVi=ΔVBE=1mvvoltage gainAV=ΔVCEΔVBE=β×RLRiΔVCE=ΔVBE×β×RLRIΔVCE=1×10−3×100×101=1.0V

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In the following common emitter configuration, an n-p-n transistor with current gain, β=100 is used. The output voltage of the amplifier will be

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In the following common emitter configuration, an n-p-n transistor with current gain, $β = 100$ is used. The output voltage of the amplifier will be