The following configuration of gates is shown in the figure below. What is the equivalent gate?

The boolean expression of this arrangement isFor OR gate,Y1=A+BFor NAND gateY2=A⋅B¯For AND gateY=Y1⋅Y2Y=(A+B)⋅(A⋅B¯)Y=(A+B)⋅(A¯+B¯)Y=A⋅A¯+B⋅A¯+A⋅B¯+B⋅B¯=B⋅A¯+A⋅B¯=XOR gate Truth Table