In the following diagram, pulley P1 is movable and pulley P2 is fixed. The value of angle θ will be

From free body diagram of pulley P1At the pulley is in equilibrium, considering horizontal direction For horizontal equilibrium,T1cos⁡θ=T2cos⁡θ⇒ T1=T2 and T1=T2=W    .......(i)Now considering for vertical equilibriumT1sin⁡θ+T2sin⁡θ=W     ....(ii)From (i) & (ii), we getWsin⁡θ+Wsin⁡θ=W∴ sin⁡θ=12 or θ=30∘