In the following figure, a body of mass m is tied at one end of a light string and this string is wrapped around the solid cylinder of mass M and radius R. At the moment t=0,the system starts moving. If the friction is negligible, angular velocity at time t would be
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a
mgRt(M+m)
b
2Mgt(M+2m)
c
2mgtR(M−2m)
d
2mgtR(M+2m)
answer is D.
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Detailed Solution
We know the tangential accelerationa=g1+ImR2=g1+1/2MR2mR2=2mg2m+M As I=12MR2 for cylinder After time t, linear velocity of mass m, v=u+at=0+2mgt2m+MSo, angular velocity of the cylinder, ω=vR=2mgtR(M+2m)